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ArithmeticExceptions and InputMismatchExceptionsThe application in Fig. H.2, which is based on Fig. H.1, uses exception handling to process any ArithmeticExceptions and InputMistmatchExceptions that arise. The application still prompts the user for two integers and passes them to method quotient, which calculates the quotient and returns an int result. This version of the application uses exception handling so that if the user makes a mistake, the program catches and handles (i.e., deals with) the exception—in this case, allowing the user to enter the input again.
1 // Fig. H.2: DivideByZeroWithExceptionHandling.java
2 // Handling ArithmeticExceptions and InputMismatchExceptions.
3 import java.util.InputMismatchException;
4 import java.util.Scanner;
5
6 public class DivideByZeroWithExceptionHandling
7 {
8 // demonstrates throwing an exception when a divide-by-zero occurs
9 public static int quotient( int numerator, int denominator )
10 throws ArithmeticException
11 {
12 return numerator / denominator; // possible division by zero
13 } // end method quotient
14
15 public static void main( String[] args )
16 {
17 Scanner scanner = new Scanner( System.in ); // scanner for input
18 boolean continueLoop = true; // determines if more input is needed
19
20 do
21 {
22 try // read two numbers and calculate quotient
23 {
24 System.out.print( "Please enter an integer numerator: " );
25 int numerator = scanner.nextInt();
26 System.out.print( "Please enter an integer denominator: " );
27 int denominator = scanner.nextInt();
28
29 int result = quotient( numerator, denominator );
30 System.out.printf( "\nResult: %d / %d = %d\n", numerator,
31 denominator, result );
32 continueLoop = false; // input successful; end looping
33 } // end try
34 catch ( InputMismatchException inputMismatchException )
35 {
36 System.err.printf( "\nException: %s\n",
37 inputMismatchException );
38 scanner.nextLine(); // discard input so user can try again
39 System.out.println(
40 "You must enter integers. Please try again.\n" ); }
41 // end catch
42 catch ( ArithmeticException arithmeticException )
43 {
44 System.err.printf( "\nException: %s\n", arithmeticException );
45 System.out.println(
46 "Zero is an invalid denominator. Please try again.\n" );
47 } // end catch
48 } while ( continueLoop ); // end do...while
49 } // end main
50 } // end class DivideByZeroWithExceptionHandling